SOLUTION: log_(4) x + log_(4) (x+6) = k. In this problem I need to solve for x. I also need to solve for x if k=10. I set up this problem as: 4^k = x(x+6) 4^k = x^2 + 6x x^2 +6x -

Question 885128: log_(4) x + log_(4) (x+6) = k.
In this problem I need to solve for x. I also need to solve for x if k=10.
I set up this problem as:
4^k = x(x+6)
4^k = x^2 + 6x
x^2 +6x - 4^k =0
Not sure where I go from here. Please help. Thank you
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Solving for x? General solution for a quadratic formula.

Assign any value you want for k and evaluate from that.
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