SOLUTION: Simplyfy (8/3)log27+(1/5)log10-(1/4)log16, (Where log2=0.3010 and log3=0.4771)

SOLUTION: Simplyfy (8/3)log27+(1/5)log10-(1/4)log16, (Where log2=0.3010 and log3=0.4771)

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Question 879667: Simplyfy (8/3)log27+(1/5)log10-(1/4)log16, (Where log2=0.3010 and log3=0.4771)
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Simplify (8/3)log27+(1/5)log10-(1/4)log16, (Where log2=0.3010 and log3=0.4771)
***
(8/3)log27=log3^8=8log3=8*0.4771=3.8168
(1/5)log10=1/5*1=1/5=0.2
(1/4)log16=log16^(1/4)=log2=0.3010
..
(8/3)log27+(1/5)log10-(1/4)log16=3.8168+0.2-0.3010=3.7158
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