SOLUTION: The directions say to solve the equation for x. -4+log9(2x)=-5 That log is supposed to have a base of 9 if that clears anything up. Could I please have detailed instructions

Question 879051: The directions say to solve the equation for x.
-4+log9(2x)=-5
That log is supposed to have a base of 9 if that clears anything up. Could I please have detailed instructions on how to solve it? I have a final tomorrow and I totally forgot how to solve this one. I tried to solve it and I have the answer because they are in the back of packet I received, but I need to know how to do it.
Thank you for your time.
Found 3 solutions by lwsshak3, josgarithmetic, MathTherapy:
Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
solve the equation for x.
-4+log9(2x)=-5
log9(2x)=-1
convert to exponential form: (base(9) raised to log of the number(-1)=number(2x)
9^-1=2x
2x=1/9
x=1/18
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!

Add +4 to both sides;
change to exponential form;

, .....
How would you prefer to find ? This would be about a nine-digit number.

(a software-program number calculator was used)
Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!

The directions say to solve the equation for x.
-4+log9(2x)=-5
That log is supposed to have a base of 9 if that clears anything up. Could I please have detailed instructions on how to solve it? I have a final tomorrow and I totally forgot how to solve this one. I tried to solve it and I have the answer because they are in the back of packet I received, but I need to know how to do it.
Thank you for your time.

18x = 1 ------ Cross-multiplying

You can do the check!!
Send comments, �thank-yous,� and inquiries to �D� at MathMadEzy@aol.com.
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