SOLUTION: Solve
a) log(base 8)(x+1) - logx = 2
Can you please help me out? Thanks so much in advance:)
Algebra.Com
Question 878648: Solve
a) log(base 8)(x+1) - logx = 2
Can you please help me out? Thanks so much in advance:)
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
I'm assuming the problem is
If so, then...
RELATED QUESTIONS
Solve
a)log(x-1) +logx = 1
Can you please help me out thanks so much in... (answered by Alan3354)
Solve
a) logx + log(x-9) = 1
Can you please help me out? Thanks so much in... (answered by jim_thompson5910)
Solve and check
a)2logm + 3logm = 10
b)log(base 3)x^2 - log(base 3)2x = 2
c)log(base... (answered by solver91311)
Solve
a)log(base 2)(x+1) + log(base 2)(x-1) = 3
b)log(base 2)(x+2) = 2 - log(base... (answered by ankor@dixie-net.com)
Solve
a) log(x-2) + log(x+1) = 1
Can you please help me out? Thanks so much in... (answered by mananth)
Solve the following
a) log(base 8)(x+9) - log(base 8)(x-1) = 1/3
Can you please... (answered by lwsshak3)
Solve
a) log(base 2)(x-5) + log(base 2) (x-2) = 2
Can you please help me out? Thanks so (answered by nerdybill)
Solve
a) log(base 5) ( r+2) +log(base 5)(r-2) = 1
Can you please help me out? Thanks so (answered by erica65404)
Solve
a) log(base 2)(2m + 4) - log(base 2) (m-1) = 3
Can you please help me out? Thanks (answered by lwsshak3)