SOLUTION: I can take 2^x=11 and solve it up to this point x=log11/log 2. I need to get the approximate answer 3.4594 I am unsure how that answer was found. Do I need a special calculator?

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Question 878599: I can take 2^x=11 and solve it up to this point x=log11/log 2. I need to get the approximate answer 3.4594 I am unsure how that answer was found. Do I need a special calculator?
Answer by Jstrasner(112)   (Show Source): You can put this solution on YOUR website!
Yes, you will need a scientific calculator or a graphing calculator.
You can also go here: http://web2.0calc.com/
I hope this helps!

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