SOLUTION: Solve each equation
1. log7^4x = log7(3x+7)
Algebra.Com
Question 877639: Solve each equation
1. log7^4x = log7(3x+7)
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Since the logs have the same base, and are equal to one another, this means the arguments (the stuff inside) must be equal
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