SOLUTION: If logb x=0.36 and logb z=0.83 What does logb (square root of x)- logb (cube root of z)= ??? I need to understand how to perform this operation. Thank you!

Question 877272: If logb x=0.36 and logb z=0.83
What does logb (square root of x)- logb (cube root of z)= ???
I need to understand how to perform this operation.
Thank you!
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
If logb x=0.36 and logb z=0.83
What does logb (square root of x)- logb (cube root of z)= ???
.
Strategy is to rewrite:
logb (square root of x)- logb (cube root of z)
in terms of what's given logb x and logb z:
rewrite original with exponents:
logb (x^(1/2))- logb (z^(1/3))
apply log rule to get:
(1/2)logb x - (1/3)logb z
substitute:
(1/2)(0.36) - (1/3)(0.83)
0.18 - 0.2767
-0.4567

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