SOLUTION: log 6 - log (5x + 5) = log 31

Question 873774: log 6 - log (5x + 5) = log 31
Found 2 solutions by josgarithmetic, lwsshak3:
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!

Take anitlogs of both sides,
no matter the base,

Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
log 6 - log (5x + 5) = log 31
log (6/(5x+5))=log(31)
(6/(5x+5)=31
31(5x+5)=6
155x+155=6
155x=-149
x=-149/155

RELATED QUESTIONS
Solve log(base 5 )... (answered by Alan3354)
solve: (log(5x-6))/log(x) = 2 (answered by dabanfield)
log(x+5)=log(5x-3) (answered by stanbon,josmiceli)
log 5x minus log 5 = log 60 No bases. (answered by MathLover1,MathTherapy)
Compute \log_4 5 + \log_5 6 + \log_6 7+ \log_{2047} 2048 + \log_{2048}... (answered by CPhill)
3 ( log 5 - log 3 ) - ( log 5 - 2 log 6 ) = 2 - log n , find n. (answered by dkppathak)
3 ( log 5 - log 3 ) - ( log 5 - 2 log 6 ) = 2 - log n , find n. (answered by nerdybill)
log(x+5)-log(x+1)=log... (answered by lwsshak3)
Log(75/76)-log(5/6)+log(32/243)=log2 (answered by jsmallt9)