SOLUTION: 2log4^(3x)=2? How to solve this..... It's log base4

SOLUTION: 2log4^(3x)=2? How to solve this..... It's log base4

Algebra.Com

Question 872071: 2log4^(3x)=2? How to solve this..... It's log base4
Answer by josgarithmetic(39623) (Show Source): You can put this solution on YOUR website!

RELATED QUESTIONS
log(base2)log(base3)log(base4)2^n=2 I don't understand how to solve... (answered by stanbon)

how to expand log base4 (3x-2)^5... (answered by tommyt3rd)

Solve: 2log(base4)x+log(base4)3=log(base4)x-log(base4)2 (answered by rapaljer)

solve for x log(base4)(x^2-3x) =... (answered by josmiceli)

Use properties of logarithms to solve the equation log(base4)(x+2)=... (answered by ewatrrr)

How do you solve log base4(x+2)... (answered by Alan3354)

Solve: {{{log(base16)(3x -1)}}} = {{{log(base4)(3x)}}}+... (answered by lwsshak3)

Solve for x: a) log base4 (x+2) + log base4 (n-4)=2 b) log base2 (x^2-2) - log base2... (answered by stanbon)

if r=log*base4* x and s=log*base4* y how can i write log*base4*(64x^(6)y^(3))^(2) using... (answered by jsmallt9)