SOLUTION: log3x+log3(x-2)=1
Algebra.Com
Question 871117: log3x+log3(x-2)=1
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
x(x-2) = 3
x^2 - 2x - 3 = 0
(x-3)(x+1) = 0, x = 3
Root x = -1 is an extraneous root
 \ = \ y \ \ \Rightarrow\ \ b^y = x)
Applied
 )
 )
 )
Applied
RELATED QUESTIONS
Solve for x:
log3^4-log3x=2
(answered by Alan3354)
please help me solve this equation log3X + log3(x+2) = 1 solve for... (answered by nerdybill)
1/3[log3(x+2)-2log3x]
I got: log3(x+2)^1/3-log3x^2... (answered by josmiceli)
logx+log3-(log3x-1)=log4
(answered by Theo)
... (answered by lwsshak3)
log3(3x)=log3x+log3(4-x) (answered by user_dude2008)
1/3 log3 x^6 +1/6 log3 x^6 - 1/9 log3x
(answered by Theo)
log3x+log(x+2)=1 (answered by nerdybill)
log3(x+6)+log3(x-6)-log3x=2
solve the logarithmic... (answered by MathLover1)