SOLUTION: How do I write log 8 - 2 log 6 - log 3 as a
Single log
Algebra.Com
Question 868475: How do I write log 8 - 2 log 6 - log 3 as a
Single log
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
write log 8 - 2 log 6 - log 3 as a
Single log
-------
log(8) - log(6^2) - log(3)
------
log(8) - log(36) - log(3)
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= log[8/(36*3)]
----
= log[2/27]
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Cheers,
Stan H.
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