SOLUTION: how do you solve the following? log3x = log4 + log (x-1) log of base 8 of x^2 = log of base 8 (3x+4) What numbers do you use to fill in for the varriables?: A=P{1+r/n}^nt

Question 868250: how do you solve the following?
log3x = log4 + log (x-1)
log of base 8 of x^2 = log of base 8 (3x+4)
What numbers do you use to fill in for the varriables?:
A=P{1+r/n}^nt
ex. Laura borrows $2500 at a rate of 10.5% compounded monthly. Find how much Laura owes at the end of 4 years.
I am studying for a quiz tomorrow and cannot get ahold of any classmates for help. Thanks.

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi















    

      3x = 4x-4

      -x = -4,   x = 4

A=P{1+r/n}^nt 

A = Accumulated Amount

P= principal = 

r= annual rate = .

n= periods per year = 

t= years =

A = 2500(1+ .105/12)^48

A = 2500(1.00875)^48 = $3,797.96

 

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