SOLUTION: 4^(3x-2)=6^x I have the solution x=1.1713 to 4 decimal places. I am just not sure what steps I need to take in order to find this solution. Please help! Thank you very much!

Question 865373: 4^(3x-2)=6^x
I have the solution x=1.1713 to 4 decimal places.
I am just not sure what steps I need to take in order to find this solution.
Please help!
Thank you very much!
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation.

Take the natural log of both sides.

Pull down the exponents.

Distribute.

Add to both sides.

Subtract from both sides.

Factor out x

Divide both sides by to isolate x.

Use a calculator to evaluate the right hand side (RHS)

Round to 4 decimal places
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