SOLUTION: If a^2+b^2=7ab how to prove log(a+b)/3=1/2(log a+log b) thank you

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Question 865138: If a^2+b^2=7ab how to prove log(a+b)/3=1/2(log a+log b)
thank you
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
a^2+b^2=7ab how to prove log(a+b)/3=1/2(log a+log b)
a^2+2ab+b^2 = 9ab
(a+b)^2=9ab
(a+b)^2/9 = ab
((a+b)/3)^2= ab
2 log (a+b)/3 = log (ab)
2 log (a+b)/3 = log a +log b
log%28a%2Bb%29%2F3+=+%281%2F2%29+%28+log+a%2Blog+b%29)