SOLUTION: If a^2+b^2=7ab how to prove log(a+b)/3=1/2(log a+log b)
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Question 865138: If a^2+b^2=7ab how to prove log(a+b)/3=1/2(log a+log b)
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Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
a^2+b^2=7ab how to prove log(a+b)/3=1/2(log a+log b)
a^2+2ab+b^2 = 9ab
(a+b)^2=9ab
(a+b)^2/9 = ab
((a+b)/3)^2= ab
2 log (a+b)/3 = log (ab)
2 log (a+b)/3 = log a +log b
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