SOLUTION: Hi, i need to find the solution set of the equation : 2 log (base 2) (x+2) - log (base 2) (7x+2) = log (base x) x^2 - log (base square root of 3) 3 Please show the solution so

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Question 864939: Hi, i need to find the solution set of the equation :
2 log (base 2) (x+2) - log (base 2) (7x+2) = log (base x) x^2 - log (base square root of 3) 3
Please show the solution so that i know what to do in the exam. Thanks.

Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
Re TY; Good Catch and Good work!



x^2 + 4x + 4 = 7x + 2
x^2 - 3x - 2 = 0
(x-2)(x-1) = 0, x = 1, 2
and IF...:)
and
Therefore:

|Note: If log(2,X) = 1 then 2^1 = X
x^2 + 4x + 4 = 14x + 4
x^2 - 10x = 0
x(x-10) = 0, x = 10 |Note: root x = 0 is an extraneous root


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