SOLUTION: How can I solve this exponential equation alegbracally? 225[(1+0.05)^x/0.05]=300000

Question 859252: How can I solve this exponential equation alegbracally? 225[(1+0.05)^x/0.05]=300000
Found 2 solutions by josmiceli, edjones:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!

Divide both sides by

Take the log of both sides

--------------------
check:

close enough

Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
225[(1+0.05)^x/0.05]=300000
4500*1.05^x=30000 multiply each side by 20.
1.05^x=200/3
log(1.05)1.05^x=x
x=log(1.05)200/3
=ln(200/3)/ln(1.05)
=~ 4.1997/.04879
=~ 86.0769
.
Ed
RELATED QUESTIONS
How can I solve this exponential equation alegbracally?... (answered by josgarithmetic)
I need to know how to solve and explain the decimal problems. "Find the unknown... (answered by math_tutor2020,MathLover1)
HOW TO SOLVE X * .05 =... (answered by solver91311)
Quadratic-relations-and-conic-sections/443131 (2011-05-01 05:06:45): I have been trying... (answered by rwm)
The data for the two variables X and Y are given in the table below: X: 1.11, 0.00,... (answered by CPhill)
i'm in pre-calculus and our teacher gave us an extra credit problem. It reads: Derive... (answered by Earlsdon)
Find the standard deviation for the given probability distribution x P(x) 0 0.05 1... (answered by ikleyn)
x P(x) 0 0.05 1 0.2 2 0.15 3 0.6 Find the standard deviation of this probability (answered by ikleyn,math_tutor2020)
how would you solve this problem:... (answered by pmatei)