SOLUTION: Log(x+2) - log(x-1) = logx

SOLUTION: Log(x+2) - log(x-1) = logx - log(x+3)

Question 855209: Log(x+2) - log(x-1) = logx - log(x+3)
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

Log(x+2) - log(x-1) - logx + log(x+3)= 0





Log (x+2)(x+3)/x(x-1) = 0       

     (x+2)(x+3)/x(x-1) = 10^0 = 1

     (x+2)(x+3)= x(x-1) 

     x^2 + 5x + 6 = x^2 - x

          6x= -6

           x = -1  Extraneous solution

 NO solution

          

        

RELATED QUESTIONS

log(x+3)=1-logx (answered by josmiceli)
log(x+3)=1-logx (answered by drk)
logx +... (answered by nyc_function)
logx-log(x-1)=2 (answered by user_dude2008)
how do you solve... (answered by Theo)
Solve log(x-1)- log6 = log(x-2)-... (answered by HyperBrain)
log(x+3)+log(x+4)=log(X3+13x2)-logx (answered by ikleyn)
log(x+2)=(logx)+... (answered by edjones)