SOLUTION: Hi, could you please help me with these problems?
1. Evaluate log3 (3^8)
2. Find value of x: log3(81) =x
3. Write equation (1/3)^-6 = 729 in logarithic form
4. Assum
Algebra.Com
Question 85509: Hi, could you please help me with these problems?
1. Evaluate log3 (3^8)
2. Find value of x: log3(81) =x
3. Write equation (1/3)^-6 = 729 in logarithic form
4. Assume x is positive number and use logarithm expression
log (x + 3) - logx
(is the answer log x+3/ x?)
Thank you for helping me with these!!!!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Comment: Remeber, log is just another word for exponent.
-------------
1. Evaluate log3 (3^8)
You want the exponent of 3 that gives you 3^8
The answer is "8".
-------------
2. Find value of x: log3(81) =x
You are told that x is exponent of 3 that gives you 81
3^x=81
x=4
---------------
3. Write equation (1/3)^-6 = 729 in logarithic form
The exponent is -6.
So write log(base 1/3) 729 = -6
-------------
4. Assume x is positive number and use logarithm expression
log (x + 3) - logx
=log[(x+3)/x]
--------------
Cheers,
San H.
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