SOLUTION: How do you solve this equation exactly for x? 2^(x^2 - x) = 4
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Question 852999
:
How do you solve this equation exactly for x?
2^(x^2 - x) = 4
Answer by
ewatrrr(24785)
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Hi,
2^(x^2 - x) = 4
2^(x^2 - x) = 2^2
x^2 - x = 2
x^2 - x - 2 = 0
(x-2)(x+1) = 0, x = 2 0r x = -1
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