SOLUTION: Evaluate 2log_6(6x)-log_6(x)^2 For whatvalues of x is the value of this expression valid? Explain. Thank you.xx

Question 846860: Evaluate 2log_6(6x)-log_6(x)^2
For whatvalues of x is the value of this expression valid? Explain.
Thank you.xx
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
The arguments (basically the terms in the logs) must be positive. You cannot take the log of 0 or a negative number.

So both 6x and x must be greater than 0.

So...

6x > 0

x > 0/6

x > 0

Which means that x > 0 in order for the expression to be valid.
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