SOLUTION: I am supposed to solve for x rounded to the nearest thousandth using logrithems: 2^(3x)=4^(x+1) Thanks

Algebra.Com
Question 833561: I am supposed to solve for x rounded to the nearest thousandth using logrithems:
2^(3x)=4^(x+1)
Thanks

Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
2^(3x)=4^(x+1)
2^(3x)=2^2*(x+1)
3x=2x+2
x=2
check
2^6=4^3

RELATED QUESTIONS

can someone please help. solve each equation for x 1. 4^(x + 1) = 4^(3x - 5) 2.8^2x (answered by stanbon)
Solve. State irrational solutions as decimal approximations rounded to the nearest... (answered by Edwin McCravy)
solve for "x" 3x+4 x+2 ---- = --- 3x-1 x-3 I don't understand how i am... (answered by Alan3354)
(Solving Natural Logarithms to solve Exponential Equations)Give an exact answer and then... (answered by nerdybill)
I need your help with this problem! Use a graphing calculator to solve the following... (answered by MathLover1)
I need your help with this problem! Use a graphhing calculator to solve the following... (answered by Gogonati,richard1234)
I have the following problem and I need to solve for x to the nearest thousandth:... (answered by josgarithmetic)
solve for x to the nearest thousandth... (answered by josmiceli)
Solve for x. Round to the nearest ten-thousandth. 6^(3x+8) =... (answered by Alan3354)