SOLUTION: i need help on solving for x in this problem, please help, thank you.
ln(x+2)+ln(2x-1)=0
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Question 825922: i need help on solving for x in this problem, please help, thank you.
ln(x+2)+ln(2x-1)=0
Found 2 solutions by josgarithmetic, stanbon:
Answer by josgarithmetic(39625) (Show Source): You can put this solution on YOUR website!
Property of Logarithms,
"ln()", means "natural logarithm of...", the base being the Euler Number, approx. 2.71828...
Two equivalent equation formulations are:
is the same as .
-----------
Your equation gives you .
Best if you understand how to obtain that, and better still if you can finish solving it. Say if you need further help.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
ln(x+2)+ln(2x-1)=0
-----
ln[(x+2)(2x-1)] = 0
----
2x^2 + 3x -2 = 1
------
2x^2 + 3x -3 = 0
------
x = [-3 +- sqrt(9-4*2*-3)]/4
------
x = [-3 +- sqrt(33)]/4
----
x = [-3 +- 5.74]/4
---
x = 0.6861
=================
Cheers,
Stan H.
================
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