SOLUTION: Solve the exponential equation. Express the solution set in terms of natural logarithms.
4^x+4 = 5^2x+5
Algebra.Com
Question 824803: Solve the exponential equation. Express the solution set in terms of natural logarithms.
4^x+4 = 5^2x+5
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve the exponential equation. Express the solution set in terms of natural logarithms.
4^(x+4) = 5^(2x+5)
-------
(x+4)ln(4) = (2x+5)ln(5)
-----------------------------
x*ln(4) + 4ln(4) = xln(5^2) + 5ln(5)
------
x[ln(4)-ln(25)] = 5ln(5)-4ln(4)
------
x[-1.8326] = 2.5020
------
x = -1.3653
============
Cheers,
Stan H.
============
RELATED QUESTIONS
Express the solution set in terms of natural logarithms.... (answered by Fombitz)
solve the exponential equation, express the solution set in terms of natural logarithms:
(answered by lwsshak3)
Solve the exponential equation. Express the solution set in terms of natural logarithms.
(answered by LinnW)
Solve the exponential equation. Express the solution set in terms of natural logarithms.
(answered by Alan3354,stanbon)
im so lost with this one...
Solve the exponential equation. express the solution set... (answered by Alan3354,jsmallt9)
solve the exponential equation. Express the solution set in terms of natural logarithms.
(answered by Alan3354)
Express the solution set in terms of natural logarithms.... (answered by Fombitz)
Solve the exponential equation. Express the solution set in terms of natural logarithms.
(answered by user_dude2008)
Find the exact solution of the exponential equation in terms of logarithms:
4^x +... (answered by Fombitz)