SOLUTION: solve log 4x = log(x+3)+log 2 for x
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Question 823746
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solve log 4x = log(x+3)+log 2 for x
Answer by
ewatrrr(24785)
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Hi,
log 4x = log(x+3)+log 2 |
log 4x = log 2(x+3)
4x = 2(x+3)
4x = 2x + 6
2x = 6
x = 3
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