SOLUTION: Log2^(x-3)=2-log2^x
Algebra.Com
Question 823455: Log2^(x-3)=2-log2^x
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
- What are you/we supposed to do with this??
- I suspect that the equation is:
If so, then there are no exponents in this equation!!
Please re-post and...- include the instructions
- don't use the exponent character, "^" when posting logs. Either...
- use some English to help describe the logs, like "base 2 log of (x-3)"
Or... - Try to learn algebra.com's syntax for formulas. Click on the "Show source" link above to see what I typed to get those logs to look like they do here.
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