SOLUTION: I need your help on logarithms: 3/4loga(p^2q^8)-1/2loga(p^5q^2). Please help me!
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Question 820404: I need your help on logarithms: 3/4loga(p^2q^8)-1/2loga(p^5q^2). Please help me!
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
3/4loga(p^2q^8)-1/2loga(p^5q^2)
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= loga[(p^2q^8)^(3/4) / (p^5q^2)^(1/2)]
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= loga[(p^(3/2)*q^6) / (p^(5/2)*q)]
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= loga[q^5/p]
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Cheers,
Stan H.
======================
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Hi,
|
=
 \ \ \Rightarrow\ \ b>0,\ \ x>0,\ \ y\ \ is\ \ a\ \ real \ \ number)
 \ = \ y \ \ \Rightarrow\ \ b^y = x)
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****
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