SOLUTION: Can I please ask for help to solve x from this question? {{{log(x, (3)) = 4}}}

Question 819231: Can I please ask for help to solve x from this question?

Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
Rewrite it in exponential form:

4th root of each side:

(Note: The zero is there only because algebra.com will not let me use the "plus or minus" sign without a number in front. You should not use the zero.)

Check. This is not optional. Use the original equation to check:

Checking :

The base is positive but not 1. So it is valid. The argument is positive so it is valid, too. So this solution checks out.
Checking :

The base is negative. This is an invalid base. So we reject this "solution".

The only solution to your equation is: . (If you need this in the form of a decimal approximation, use in your calculator.)
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