SOLUTION: Prove that, 7log16/15+5log25/24+3log81/80=log2.

Algebra.Com
Question 818767: Prove that, 7log16/15+5log25/24+3log81/80=log2.
Answer by jsmallt9(3758)   (Show Source): You can put this solution on YOUR website!
Note: In the future please put parentheses around function arguments.


What we will be doing is using properties of logarithms (, and/or ) to condense the entire left side into a single logarithm (hopefully log(2)).

We'll start by using the third property to move the coefficients of each log into its argument as its exponent:

Next we can use the first property to combine the three logs:

To make simplifying the argument easier, I am going to rewrite each numerator and denominator in terms of prime factors:

Now we can use the rule to raise each of these fractions to a power:

Using the rule to multiply the numerators and denominators:

The 3's and 5's all cancel out. And we can use the rule to divide the 2's:


Check!

RELATED QUESTIONS

7log16/15-5log24/25+3log81/80 (answered by Alan3354)
proove that log2 + 16log16/15 + 12log25/24 + 7log81/80 =... (answered by lwsshak3)
prove... (answered by Boreal)
show that... (answered by stanbon)
Show that... (answered by jsmallt9)
7log(16/15)+5log(25/24)+3log(81/80)=log2 (answered by Fombitz)
Simplify... (answered by Alan3354)
Prove that... (answered by Boreal)
Prove that log(1+2+3)= log1+... (answered by Alan3354,josmiceli)