SOLUTION: S(x)=-4x^2-1 and w(x)=3x+1, find (sw)(2) (sw)(2)=

Algebra.Com
Question 818462: S(x)=-4x^2-1 and w(x)=3x+1, find (sw)(2)
(sw)(2)=

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
S(x)=-4x^2-1 and w(x)=3x+1, find (sw)(2)
-------
Comment: I think you probably want the composite, SoW(x).
--------
SoW(x) = S[W(x)] = S[3x+1] = -4(3x+1)^2-1 = -4[9x^2+6x+1]-1
-----
= -36x^2 -24x -5
==========================
(SoW)(2)= S[W(2)] = S[7] = -4(49)-1 = -197
==========================
Cheers,
Stan H.
--------------

RELATED QUESTIONS

in parallelogram RSTW, diagonals RT and SW intersect at point A. If SA = x+2 and AW =... (answered by Boreal)
Make S as a Subject of the formula? r=z(e^sw/kp-2) (answered by Alan3354)
Br resolving the forces horizontally and vertically, find the magnitude and direction of... (answered by josgarithmetic)
a=... (answered by Alan3354)
A=Sw+w (answered by ikleyn)
In a parallelogram, diagonals RT and SW intersect at point A. If SA=x-13 and AW= 2x-37,... (answered by ikleyn)
In the diagram, $ABCD$ is a square. Find $PR.$ [asy] unitsize(1.5 cm); pair A, B,... (answered by ikleyn)
Another Quadtic Formula: Solve by FACTORING...... problem: 2a^^2 + 1= -3a Now I... (answered by 303795)
Find the product:... (answered by jim_thompson5910)