SOLUTION: log5(3x+7) + log5(x-5)= 2

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Question 818289: log5(3x+7) + log5(x-5)= 2
Found 2 solutions by LinnW, MathTherapy:
Answer by LinnW(1048)   (Show Source): You can put this solution on YOUR website!
log5(3x+7) + log5(x-5)= 2log5(5)
log5(3x+7) + log5(x-5)= log5(5^2)
log5( (3x+7)/(x-5) ) = log5(25)



Subtract 3x from each side.

Add 125 to each side.
132 = 22x
6 = x
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
log5(3x+7) + log5(x-5)= 2 












(3x + 10){x - 6) = 0

3x = - 10             OR        x = 0 + 6

               OR        

Since  will yield the log of a negative number, so ignore this solution. Thus, the only solution is: 

You can do the check!!



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