SOLUTION: Please help me figure this out. log(base7)x

SOLUTION: Please help me figure this out. log(base7)x - log(base7)(3x-5)=1

Question 817316: Please help me figure this out. log(base7)x - log(base7)(3x-5)=1
Answer by LinnW(1048) (Show Source): You can put this solution on YOUR website!
log(base7)(7) = 1, think 7^1 = 7
so log(base7)(x) - log(base7)(3x-5) = log(base7)(7)
Since in general log(u/v) = log(u) - log(v)
log(base7)( x / (3x-5) ) = log(base7)(7)
So x / (3x-5) = 7/1
x = 7(3x-5)
x = 21x -35
-20x = -35
x = 35/20
x = 7/4

RELATED QUESTIONS
log(base7)x+log(base7)(x-1)=log(base7)12 (answered by lwsshak3)

log(base7)1=0 (answered by fcabanski)

could anybody please help me evaluate this example 1/3logbase7^125+log base7 ^0.2 - log... (answered by jsmallt9)

Okay. My question is this... Log base7 3x-log base7 9x +log base7 6y I don't know... (answered by vleith)

log base7... (answered by stanbon)

Solve... (answered by jim_thompson5910)

Hi, I have a maths test tomorrow and i am pretty much sweet except for one thing.... (answered by addingup,ikleyn,MathTherapy)

Solve the equation 3log[base5]x - log[base5]4 = log[base5]16. Solve the equation... (answered by drk)

log base 7 (x+6) - log base7 (x-3)= log base7... (answered by jsmallt9)