Hi,

log 3 + log (x + 1) = log (2x + 4)  |  1st step would be to get them on one side of the EQ  

log 3 + log (x + 1)- log (2x + 4) = 0  | write as one Logarithm

 Apply: and 

             Apply: 

 

    3x+ 3 = 2x + 4

       x = 1  

CHECKING our answer***

log 3 + log (x + 1) = log (2x + 4) 

log 3 + log (2) = log (6)     

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