SOLUTION: I am taking an online electronics course and I am stumped on decibel/logarithm section relating to amplifiers. My problems deal in power or voltage gain, and levels. Here are 2 e

Question 81388: I am taking an online electronics course and I am stumped on decibel/logarithm section relating to amplifiers. My problems deal in power or voltage gain, and levels. Here are 2 examples that I cannot solve. (1) A power amplifier has a gain of 26dB, and an input of 1 volt. What is the voltage level? (2) An amplifier has a voltage gain of 60dB, the input is 10 microvolts, what is the output? I have a couple formulas, and I know the answers, but I can't figure out how to get the answers from the formulas. The answer to problem one is 20, and the answer to problem 2 is 10. Here are the formulas:
Gain= signal out/signal in
dB= 10 x log(base 10) (W out/ W in)
dB= 20 x log(base 10) (V out/ V in)
Output voltage= input level x gain ratio
I need a very detailed expression as to how to solve these problems. I have looked in two textbooks for further explanation, but I cannot find the solutions.
Thank you so much if you can help!!!!

Answer by bucky(2189) (Show Source): You can put this solution on YOUR website!
To solve these two problems you need only the voltage amplification equation:
.

.
and a knowledge of a few rules of Logarithms.
.
The dB equation defines decibels. It uses the base 10 Logarithms. In this equation,
is the output voltage, and is the input voltage.
.
Here are a couple of rules of Logarithms that you should be familiar with. Assume that
the base of the Logarithm is b:
.
Rule I. �.
.
Rule II. �. �
.
Rule III. �. +
.
Rule IV. �. Log base b of x = y is equivalent to saying
.
Note that in decibel calculations b (the base) is 10. This translates Rule IV to:
.
Log (x) = y is equivalent to saying
.
If you need a further explanation of these rules, you can get it from an Algebra II text,
from elsewhere on this site, or by doing a Google on Logarithms.
.
Time to work your first problem by using the voltage form of the decibel equation.
Given the amplifier has a power gain of 26 dB, and an input voltage of 1 volt. Substitute
those two values into the dB equation (26 for dB and 1 for the input voltage) and you get:
.

.
The plan is to work down to , so start by dividing both sides of this equation by
20 to get rid of the 20 on the right side. At the same time note that
is just . These simplifications lead to the equation becoming:
.

.
And after dividing 26 by 20 on the left side the equation reduces to:
.

.
Time to apply Rule IV. When you do you get:
.

.
Calculator time. Your calculator probably works this way: enter 1.3 then press the
key and you find the result to be 19.95262315 volts. Close enough for electrical work.
Call it 20 volts.
.
Now to your second problem. If the answer is to be 10, then you probably meant that the
input voltage was 10 millivolts instead of 10 microvolts .
So let�s use 10 millivolts.
.
For the given gain of 60 dB and an input of volts the equation becomes:
.

.
Just as was done in the last problem, divide both sides by 20 to reduce the problem to:
.

.
The left side divides out to a quotient of 3 and the equation becomes:
.

.
On the right side apply Rule II (division) to split the term into two separate logarithms:
.
�
.
Notice that 10*10^-3 = 10^(-2). Substitute this into the right hand logarithm and get:
.
�
.
Apply Rule I (exponent rule) to and get - . But by Rule IV
you can see that Log base 10 of 10 = 1. (Think which means y must be 1.)
So - equals -2*1 equals -2. Substitute this result for �
and the equation becomes:
.
�
.
And this simplifies to
.
Subtract 2 from both sides and the equation becomes:
.

.
Apply Rule IV to this equation and you get:
.

.
This agrees with the answer you had for this problem, but recall that 10 millivolts
was used in place of 10 microvolts to get the answer.
.
Hope this helps you get a handle on decibel equations.

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