SOLUTION: log4(b+27)-log4(b-7)=log4b
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Question 810861: log4(b+27)-log4(b-7)=log4b
Found 2 solutions by josmiceli, stanbon:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
( I'll use instead of )
and
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Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log4(b+27)-log4(b-7)=log4b
log4(b+27) = log4(b-7)+log(4b)
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log4(b+27) = log[4b^2-28b]
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b+27 = 4b^2-28b
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4b^2 -29b -27 = 0
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Positive solution:
b = 8.0849
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Cheers,
Stan H.
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