SOLUTION: what is the Logarithmic equation for: 27^(-2/3)=(1/9)

Algebra.Com
Question 808663: what is the Logarithmic equation for:
27^(-2/3)=(1/9)

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
what is the Logarithmic equation for:
27^(-2/3)=(1/9)
------------------
The log is the exponent.
The number to the left of the exponent is the base.


----

RELATED QUESTIONS

What is the positive root of the equation 3x²-27=0? 1)9 2)-9 3)3... (answered by anantha)
What is the solution set for the logarithmic equation: log(2)x^2+4=3 (answered by solver91311)
what is the equation in logarithmic form for 16=(1/4)-2? (answered by Theo)
For this problem I must write the logarithmic equation in exponential form. For example... (answered by Earlsdon)
9 1/2=3 convert to a logarithmic equation (answered by Alan3354)
How do i express 27^-2/3 = 1/9 in logarithmic... (answered by jim_thompson5910)
convert to logarithmic equations 9 3/2 =... (answered by lwsshak3)
Write the equation in logarithmic form... (answered by Alan3354)
Write the equation in its equivalent logarithmic form. 3^-2=1/9 thanks =) (answered by AAfter Search)