SOLUTION: Please help me solve this logarithm: log5 (2x^2 - 3x + 1) - log5 (x - 1) + log5 125 = 6. If you could, please show step by step. Thank you.

SOLUTION: Please help me solve this logarithm: log5 (2x^2 - 3x + 1) - log5 (x - 1) + log5 125 = 6. If you could, please show step by step. Thank you.

Algebra.Com

Question 808456: Please help me solve this logarithm: log5 (2x^2 - 3x + 1) - log5 (x - 1) + log5 125 = 6. If you could, please show step by step. Thank you.
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!

............in base 10

.....if log same, then

......simplify

RELATED QUESTIONS
Can you help me solve this problem Solve. Log5 (3x+1)- Log5... (answered by jsmallt9)

Please help me solve log5 (4x-1) is greater than or equal to log5 (x+2). By the way, 5 is (answered by Alan3354)

Please help me solve 2x^2-x>3 and condense and simplify 2logx -log5-log(x+1). Thank... (answered by jsmallt9)

90) 3^2x -8 . 3^x +15=0 94) If x= (log125 5)^log5 125 Please help me to solve (answered by jim_thompson5910)

90) 3^2x -8 . 3^x +15=0 94) If x= (log125 5)^log5 125 Please help me to solve (answered by stanbon)

Solve for x... (answered by nerdybill)

Please Help Me Condense this expression log5 10+log5 2-log5 4 Show... (answered by lwsshak3)

How do you condense this? 1/2(log5(x)+log5(y))-2... (answered by LinnW)

Solve for x: log5 x + log5(x-24) = 2 Please show me how you got the answer,... (answered by josgarithmetic,MathLover1,greenestamps)