SOLUTION: Solve using Algebra:
log(1/3x)-5 =2
e^x+3.2 = 4.7
Algebra.Com
Question 808262: Solve using Algebra:
log(1/3x)-5 =2
e^x+3.2 = 4.7
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Solve using Algebra:
add 5 to both sides
Exponent equiv of logs
:
e^x+3.2 = 4.7
e^x = 4.7-3.2
e^x = 1.5
x = ln(1.5)
x = .405
RELATED QUESTIONS
Solve the following:
log(7)24−log7(x+5)=log(7)8... (answered by harpazo)
solve for x:
1) 2log(2x+8)=4
2) logx-log4=-2
3) e^ln5x=20
4) e^x+6 + 5=1
5)... (answered by ewatrrr)
Please solve these .
*WHEN I PUT LOG(3) THAT IS A SUBSCRIPT *... (answered by Alan3354)
I have been having a really hard problem with these logs
1. Log base 8 X=1/3
2. Log (answered by alicealc,nerdybill)
1. 5*7^0 =
2. 1/4-^2 =
`
3. (1/4) ^-1/2 =
4. (bm)^-3=
5. y^-5/y^-2 =
6.... (answered by edjones)
Solve for x:... (answered by venugopalramana,sdmmadam@yahoo.com)
solve the equation:
1)3 ln 3x =6
2) ln √x+7 =4
3)ln(3x-4) =ln(4)-ln(x-1)... (answered by lwsshak3)
Solve for x:
A.) Log(base 3)4 + log(base 3)5 = log(base 3)(4x+5)
B.)log(base 7)6... (answered by algebrapro18)
solve for x 2+4(5)^x=16
Solve for x Log of 7 (5x-1)=2
Log of 2 (1- x) - Log of 2... (answered by stanbon)