SOLUTION: Solve and check log(3x+2) + log(x-1) =2 Can you please help me out? Thanks so much in advance :)

SOLUTION: Solve and check log(3x+2) + log(x-1) =2 Can you please help me out? Thanks so much in advance :)

Algebra.Com

Question 807905: Solve and check
log(3x+2) + log(x-1) =2
Can you please help me out? Thanks so much in advance :)
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Solve and check
log(3x+2) + log(x-1) =2
log(3x+2)(x-1)=2
log(3x+2)(x-1)=log(100)
(3x+2)(x-1)=100
3x^2-x-102=0
(3x+17)(x-6)=0
x=-17/3 (reject,(x-1)>0)
or
x=6
Check:
log(3x+2)=log(20)
log(x-1)=log(5)
log(20)+log(5)=2
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