SOLUTION: log(base4)(x-9)-log(base4)(x+3)=2

Question 806760: log(base4)(x-9)-log(base4)(x+3)=2
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
log(base4)(x-9)-log(base4)(x+3)=2
***

convert to exponential form
4^2=(x-9)/(x+3)=16
16(x+3)=x-9
16x+48=x-9
15x=-57
x=-57/15
no solution: (x+3)>0
RELATED QUESTIONS
Solve: 2log(base4)x+log(base4)3=log(base4)x-log(base4)2 (answered by rapaljer)

log(base4)(x-3)+log(base4)(x+9)=3 (answered by tommyt3rd,josmiceli)

Log base4 (x^2 - 3) + Lobg base4... (answered by Earlsdon)

Log base4 (x+5) = log base4... (answered by jim_thompson5910)

Log(base4)(2x+1)=Log(base4)(x-3)+Log(base4)(x+5) (answered by Nate)

Solve: 2 * log--base4 (x) + 3 * log--base8... (answered by lwsshak3)

Solve for x: log base4 (x) + log base 4 (x+3) = log base4... (answered by lwsshak3)

expand... (answered by ewatrrr)

How do you solve log base4(x+2)... (answered by Alan3354)