SOLUTION: How do I solve the following problems
logx + log1.4 =2
lnx - ln1.4 =2
and
log(3x) - log1.3 = 2.4
ln(3x) + ln 1.3 = 2.4
I have tried dividing such as to find x
Algebra.Com
Question 806318: How do I solve the following problems
logx + log1.4 =2
lnx - ln1.4 =2
and
log(3x) - log1.3 = 2.4
ln(3x) + ln 1.3 = 2.4
I have tried dividing such as to find x
logx + log1.4 =2
---- ------
log log = 1.4=2 == .7
I do not think this is correct. Please show me where I am going wrong.
Thank you
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
The base is , so
--------------
check:
close enough
-------------------
---------------
check:
close enough
--------------
You get the idea now
RELATED QUESTIONS
Question: Determine the values of "x" that satisfy the equation (x^2+3x-9)^(2x-8)=1... (answered by josgarithmetic,MathTherapy)
log1/2 16 =... (answered by KMST)
Solve:
log base 4 (X) + Log base 8 (x) = 1
ln X/ln 4 + ln X/ln 8=1
2 ln X/2 ln 4 + ln... (answered by Fombitz)
Simplify logarithms to rewrite the following expressions in terms of u and t. Let ln x=t... (answered by Tatiana_Stebko)
solve the equation:
1)3 ln 3x =6
2) ln √x+7 =4
3)ln(3x-4) =ln(4)-ln(x-1)... (answered by lwsshak3)
How do I solve these problems?
1. ln(5 - x) + ln(-3 - x) = ln(1 - 8x)
2.... (answered by josgarithmetic,MathTherapy)
ln(x+2)-ln(4)=-lnx
(answered by josgarithmetic)
lnx+ln(x+2)=4 (answered by bucky)
lnx+ln(x+2)=4 (answered by Edwin McCravy)