SOLUTION: Find an equation to the tangent line to the curve at the given point.
y=ln(x^2-6x+1) at (6,0)
I got the answer y=6(x-0)+6 but it was wrong.
Algebra.Com
Question 804710: Find an equation to the tangent line to the curve at the given point.
y=ln(x^2-6x+1) at (6,0)
I got the answer y=6(x-0)+6 but it was wrong.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
)
Let 
You can calculate )
for yourself.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
RELATED QUESTIONS
find an equation of the tangent line to the curve at the given point y=sqrt 1+x^3... (answered by Fombitz)
find an equation of the tangent line to the curve at the given point y=x+tanx... (answered by htmentor)
Write an equation of the line tangent to the circle given by (x^2 + y^2 - 6x - 4y + 8 =... (answered by josgarithmetic)
Find the equation of the tangent line to the curve {{{(x-y)^2}}}{{{""=""}}}{{{2x+1}}}... (answered by Edwin McCravy)
Find the equation of the tangent line to the curve (x-y)^2=2x+1 at the point... (answered by Alan3354)
Find the equation of the tangent line to the curve (x-y)^2=2x+1 at the point... (answered by Fombitz)
Find an equation of the tangent line to the following graph at the given point... (answered by robertb)
A curve is given: y = e^-x^2. Find the point on the curve where the slope of the tangent... (answered by Fombitz)
Find an equation of the tangent line to the curve y=e^x/(1+2e^x ) at the point whose... (answered by MathLover1)
