SOLUTION: I would like a solution to how it is done to evaluate each expression: -2+ 1n e^3. I do know the answer is 1 (from the back of my text book's answers to the problem), but the l

Algebra ->  Algebra  -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I would like a solution to how it is done to evaluate each expression: -2+ 1n e^3. I do know the answer is 1 (from the back of my text book's answers to the problem), but the l      Log On

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Question 80373This question is from textbook Algebra for college students
: I would like a solution to how it is done to evaluate each expression:
-2+ 1n e^3. I do know the answer is 1 (from the back of my text book's answers to the problem), but the log calculator on this web site had the answer as 0 because it was needed 0 divisions to get to 1. Please explain .
This question is from textbook Algebra for college students

Answer by stanbon(29603) About Me  (Show Source):
You can put this solution on YOUR website!
-2+ 1n e^3.
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You have to know that lne^x = x
Why?
Well, ln means log(base e)
So lne^3 means log(base e) e^3, and that log is 3
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Wow, that was a mouthful.
Anyway, for your problem:
-2 + lne^3
= -2 + 3
=1
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Cheers,
Stan H.