SOLUTION: Solve for x. Log base 9 (x-6) + log base 9 (x+2)=1

Question 798460: Solve for x.
Log base 9 (x-6) + log base 9 (x+2)=1
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Solve for x.
Log base 9 (x-6) + log base 9 (x+2)=1

convert to exponential form: (base(9) raised to log of number(1)=number(x-6)(x+2)
9^1=(x-6)(x+2)
9=x^2-4x-12
x^2-4x-21=0
(x+3)(x-7)=0
x=-3(reject,(x-6)>0)
or
x=7
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