SOLUTION: Evaluate log2(3) x log3(4) x log4(5) x log5(6) x log6(7) x log7(8)

Algebra.Com
Question 791592: Evaluate log2(3) x log3(4) x log4(5) x log5(6) x log6(7) x log7(8)
Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
Evaluate
Assume the problem is:
= ?
Not sure if there is an easier way to do this, but it can be done using the
change of base formula: =
:
A lot of math, so wrote a 10 line basic program that spit it out in milliseconds.
the quotient of these 6 expressions was exactly 3
Interesting that integer values occur:
the quotient of the 1st two = 2
the quotient of the given 6 = 3
the quotient of expressions up = 4
the quotient of expressions up = 5
the quotient of expressions up = 6
the quotient of expressions up = 7
:
Not sure how relevant this is to anything, but thought it was interesting. CK
Comments? email me at: ankor@att.net

RELATED QUESTIONS

log8(3x-2)=2 log2(4x)-log2(3=6) 4e^2x+1=12 log6(x+6)+log6(2=2) log3[log2(x+5)]=1... (answered by stanbon)
(1) log3 1/9 (2) log3^3 +log3^9 (3) log6 216=3 (4) log8 4 + log8 16 (5) log12 288-... (answered by MathLover1,MathTherapy)
x=log196 y=log225 z=log256 Express the following in terms of x, y, and/or z 1.... (answered by Alan3354)
solve the equation log8(3x+7)=log8(7x-9) log4(x)=3/2 loga(1/8)=-3... (answered by jsmallt9)
1. Identify the equation that represents the function in the following graph. (answered by Alan3354)
Solve for x Log2(10x)=log2(3x+14) 2log3^x=log3^4 Log5(4x-3)=log5(x+1) (answered by Alan3354)
log516 - log52t = log52 log5m = log5125 logy = log16 + log49 log6(b2 + 2) +... (answered by mukhopadhyay)
log7 (x+3)- log7 (x-3)=1 log3 (y-8)+ log3 (y=4)= log3 13 log2 84 I need to solve... (answered by stanbon)
Simplify the following expressions: log36 - log3 + log2 6 X log2 - 2 X log4 (answered by lwsshak3)