SOLUTION: How do I solve this simultaneous logarithm.
log (x-4)+ 2 log y = log 16
log x + log y = 16
Algebra.Com
Question 787559: How do I solve this simultaneous logarithm.
log (x-4)+ 2 log y = log 16
log x + log y = 16
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log (x-4)+ 2 log y = log 16
log x + log y = 16
---------
Modify for elimination:
log(x-4) + 2log(y) = log(16)
2log(x) + 2log(y) = 32
------
Subtract and solve for "x":
2log(x) - log(x-4) = 32-log(16)
--------
log(x^2) - log(x-4) + log(16) = 32
----------------
log[16x^2/(x-4)] = 32
-----------------
16x^2/(x-4) = 10^32
----
16x^2 -10^32x -4*10^32 = 0
----
Solve for "x"; then solve for "y".
=============================
Cheers,
Stan H.
===============
RELATED QUESTIONS
Please help me solve this
{{{ log( 2, x ) + log( 4, y ) + log( 4, z ) }}}
{{{ log( 3, (answered by lwsshak3)
How do i write these as a single logarithm?
1) (log 3 - log 4) - log 2
2) log 2 +... (answered by Boreal)
How do I write log x + log 7 - log y as a single... (answered by nerdybill)
Solve the equation {{{log(16,(x))+log(8,(x))+log(4,(x))+log(2,(x))=6}}} (answered by jim_thompson5910)
log x + log (x2 - 16) - log 7 - log (x - 4)
(answered by amarjeeth123)
How do I condense this expression to a single logarithm?
{{{ log z+log x / 3 + log y /... (answered by lwsshak3)
How do you write this as a single logarithm: 1/3(log x + log z) - 2 log... (answered by dnanos,Edwin McCravy)
log y... (answered by jsmallt9)
Let x = log 2, y = log 3, and z = log 10.
Express the logarithm in terms of x, y, and z.
(answered by lwsshak3)