SOLUTION: how do i solve for x when 0.83=logx
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Question 783665: how do i solve for x when 0.83=logx
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ =\ y\ \Leftrightarrow\ b^y\ =\ x)
Since the base isn't specified, assume 
You will need your calculator for 
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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