SOLUTION: How do I rewrite the expression 5logx - 4log(x^2+1) + 2log(x-1) as a single logarithm? I changed the logs to : log(x^5) - log(x^2+1)^4 + log(x-1)^2 But from there I am stuck...

Algebra.Com
Question 782611: How do I rewrite the expression 5logx - 4log(x^2+1) + 2log(x-1) as a single logarithm?
I changed the logs to : log(x^5) - log(x^2+1)^4 + log(x-1)^2
But from there I am stuck...

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
5log(x) - 4log(x^2+1) + 2log(x-1)

log(x^5) - log( (x^2+1)^4 ) + log( (x-1)^2 )

log(x^5) + log( (x-1)^2 ) - log( (x^2+1)^4 )

log( x^5(x-1)^2 ) - log( (x^2+1)^4 )

log[ ( x^5(x-1)^2 )/(x^2+1)^4 ]

Hopefully all that makes sense. If not, please let me know. Thanks.

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