SOLUTION: Solve Log(x+2)+Log(x-1)=Log(70)

Question 773143: Solve

Log(x+2)+Log(x-1)=Log(70)
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
..write left side as single log

.....if log same, then
is same too; now, solve for

...write as
..group
...factor

solutions:
if =>
if =>
so, we need DISABLED_event_only= > .....your answer

RELATED QUESTIONS
solve log(x+4) = log(5x + 1) + log... (answered by Fombitz)

log(log x) =... (answered by stanbon)

log(log x) =... (answered by nerdybill)

log(log(x))=2 (answered by Edwin McCravy,stanbon)

solve for x: log(x + 2) +... (answered by stanbon)

Solve for x. a.) log sub2(log sub4{log sub3[log sub2 x]}) = -1 b.) log sub2(x+4)... (answered by MathLover1)

log(x + 3) = 1 - log(x - 2) Solve for x (answered by ewatrrr,MathLover1)

solve for x: log x + log(x-1) =... (answered by nerdybill)

log(x-1)+log(x+1)=Log(x+2)^2 (answered by stanbon)