SOLUTION: write the expression as a single logarithm using the addition and subtraction method log(x^2+2x-3)/(x^2-4)-log(x^2+7x+6)/(x+2) "log(x^2+2x-3)/(x^2-4)-log(x^2+7x+6)/(x+2) log(

Question 768328: write the expression as a single logarithm using the addition and subtraction method
log(x^2+2x-3)/(x^2-4)-log(x^2+7x+6)/(x+2)
"log(x^2+2x-3)/(x^2-4)-log(x^2+7x+6)/(x+2)
log((x^2+2x-3)/(x^2-4)/(x^2+7x+6)/(x+2))
log(((x+3)(x-1)/(x+2)(x-2))/((x+6)(x+1)/(x+2)))
log(((x+3)(x-1)/(x+2)(x-2))*((x+2)/(x+6)(x+1)))
(x+2) cancels out"-iwsshak3
would the simplified addition and subtraction logarithm look like this
log(x+3)+log(x-1)-log(x+2)+log(x-2)+log(x+2)-log(x+6)+log(x+1)
once again thank for the help i might be over thinking the problem

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
write the expression as a single logarithm using the addition and subtraction method

=
Invert divisor and multiply
=
=
Cancel x+2
=
===============
That's a single log, what was asked for.

RELATED QUESTIONS
Write expression as a single Logarithm... (answered by MathLover1)

write the expression as a single logarithm log(x^2+2x-3)/(x^2-4)-log(x^2+7x+6)/(x+2) (answered by lwsshak3)

evaluate the logarithm. 1. log (base 7) 1/49 write the expression as a single... (answered by nerdybill)

Using laws of logarithms, write the expression below as a single logarithm 6 log(25-x^2) (answered by MathLover1)

Using laws of logarithms, write the expression below as a single logarithm 6 log(25-x^2) (answered by stanbon)

express as a single logarithm log(x^2+2x-3/x^2-4)-log(x^2+7x+6/x+2) Thank you so... (answered by arunpaul)

2log2+3 log x-1/2[log(x+3)+log(x-2)] write this expression as a single logarithm (answered by lwsshak3)

How do I write these as the logarithm of a single expression...... (answered by Big Poop)

How do I write these as the logarithm of a single expression... log(x^2+3x-10)-log(x+5) (answered by stanbon)